True, Equivalent, and Calibrated Airspeeds |
|
The energy equation for adiabatic flow of an ideal gas is |
|
|
|
where v is the flow velocity and h is the specific enthalpy. This implies that if a flow with free stream velocity v0 and enthalpy h0 is brought to rest adiabatically, and if h1 is the enthalpy of the resting gas, then |
|
|
|
Also, for an ideal gas we have dh/dT = cp, where the specific heat cp is essentially constant for relatively small changes in temperature, so this equation can be written as |
|
|
|
Now, the speed of sound in an ideal gas is given by |
|
|
|
Also, for an ideal we have R = cp cv, so we can make this substitution, divide through by a02, and re-arrange terms to give |
|
|
|
The ratio v0/a0 is, by definition, the Mach number M of the free stream, and since temperature is proportional to the square of the speed of sound, the ratio (a1/a0)2 equals the ratio of temperatures T1/T0. Hence we have |
|
|
|
Furthermore, using the ideal gas equation p = ρRT we can substitute for the temperatures to give |
|
|
|
As discussed in The Speed of Sound, for an adiabatic quasi-static (i.e., isentropic) process, the ratio p/ργ is constant. Thus if we re-write the above equation as |
|
|
|
the first factor on the left side is unity, and we arrive at the formula for the isentropic pressure rise of an ideal fluid being brought to a stop from a Mach number M |
|
|
|
Solving this
equation for M and then multiplying through by the freestream speed of sound |
|
|
|
In some primitive systems, only the quantity called dynamic pressure was measured. For incompressible fluids this quantity is |
|
|
|
For convenience we can define a quantity called equivalent airspeed to be the airspeed that would exist with sea level ISA density ρ* rather than the actual density at the given flight condition. Thus we have |
|
|
|
So, recalling that p = ρRT, we have |
|
|
|
Where T* = 518.67 R and p* = 14.696 psia, and we define and θ = T0/T*, and δ = p0/p*. For reference, we also note the speed of sound at sea level standard day conditions: |
|
astandard = √(γRT*) = 1116 ft/sec = 661.47 knots |
|
With certain kinds of primitive instrumentation systems we can measure only the difference p1 p0 between the total and static pressures. This difference is sometimes called the impact pressure, which is the same as the dynamic pressure (1/2)ρv2 for incompressible flow, but not for compressible flow. Even if we can re-write the ratio p1/p0 as (p1 p0)/p0 + 1, we would still need to know the static pressure p0 (in addition to the impact pressure) in order to compute equivalent airspeed. However, lacking the static pressure, we can agree by convention to simply use the standard sea level static pressure p* in place of p0. When this is done, we get the following formula for calibrated airspeed as a function only of the impact pressure |
|
|
|
where pstandard = 14.696 psia. Given the definition of calibrated airspeed, we sometimes need to compute it based on the actual measured values of the static pressure p0 and freestream Mach number M. (Of course, knowing p0 and M, we could compute equivalent airspeed, but convention may still force us to deal with calibrated airspeed.) For convenience, we will set γ = 1.4, which is the value for atmospheric air. Then p1 is given in terms of p0 and Mach by the relation |
|
|
|
Substituting this into the calibrated airspeed equation gives |
|
|
|
where δ
denotes the pressure ratio p0/pstandard. For values of
M less than |
|
|
|
In terms of the true airspeed this is |
|
|
|
For small Mach numbers (much less than 1) the zeroth order term of the expansion is often accurate enough for practical purposes, but for Mach numbers approaching 1 it is necessary to take account of the higher-order terms or else simply use the exact analytical expression. |
|